Pythagorean Theorem

math
How did I not know this
Author

Steve Linberg

Published

February 2, 2022

How did I make it to $adulthood * 2 without knowing that our old friend, the Pythagorean Theorem (\(a^2 + b^2 = c^2\)), works in any number of dimensions?

The Euclidean distance \(d\) between the origin (\(0, 0, \dots 0\)) and a point defined by \(n\) coordinates \(x\) is just

\[d = \sqrt{x_1^2 + x_2^2 + \dots + x_n^2}\]

Add up all of the squares and take the square root. Dope-smack for me.

Reuse

Citation

BibTeX citation:
@online{linberg2022,
  author = {Steve Linberg},
  title = {Pythagorean {Theorem}},
  date = {2022-02-02},
  url = {https://slinberg.net/posts/2022-02-02-pythagorean-theorem},
  langid = {en}
}
For attribution, please cite this work as:
Steve Linberg. 2022. “Pythagorean Theorem.” February 2, 2022. https://slinberg.net/posts/2022-02-02-pythagorean-theorem.